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DataFormat 是一個專門處理日期輸出的 class
讓輸出的日期是我們所期望的格式
其設定的 format 往往長這樣 "yyyy-MM-dd"
究竟這一串倒底是什麼意思呢？
就由官方提供的下表來為大家解答吧
| Letter | Date or Time Component | Presentation | Examples |
|---|---|---|---|
G |
Era designator | Text | AD |
y |
Year | Year | 1996; 96 |
M |
Month in year | Month | July; Jul; 07 |
w |
Week in year | Number | 27 |
W |
Week in month | Number | 2 |
D |
Day in year | Number | 189 |
d |
Day in month | Number | 10 |
F |
Day of week in month | Number | 2 |
E |
Day in week | Text | Tuesday; Tue |
a |
Am/pm marker | Text | PM |
H |
Hour in day (0-23) | Number | 0 |
k |
Hour in day (1-24) | Number | 24 |
K |
Hour in am/pm (0-11) | Number | 0 |
h |
Hour in am/pm (1-12) | Number | 12 |
m |
Minute in hour | Number | 30 |
s |
Second in minute | Number | 55 |
S |
Millisecond | Number | 978 |
z |
Time zone | General time zone | Pacific Standard Time; PST; GMT-08:00 |
Z |
Time zone | RFC 822 time zone | -0800 |
然後是範例的表格
| Date and Time Pattern | Result |
|---|---|
"yyyy.MM.dd G 'at' HH:mm:ss z" |
2001.07.04 AD at 12:08:56 PDT |
"EEE, MMM d, ''yy" |
Wed, Jul 4, '01 |
"h:mm a" |
12:08 PM |
"hh 'o''clock' a, zzzz" |
12 o'clock PM, Pacific Daylight Time |
"K:mm a, z" |
0:08 PM, PDT |
"yyyyy.MMMMM.dd GGG hh:mm aaa" |
02001.July.04 AD 12:08 PM |
"EEE, d MMM yyyy HH:mm:ss Z" |
Wed, 4 Jul 2001 12:08:56 -0700 |
"yyMMddHHmmssZ" |
010704120856-0700 |
"yyyy-MM-dd'T'HH:mm:ss.SSSZ" |
2001-07-04T12:08:56.235-0700 |
資料來源：
http://docs.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html
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